Friday, September 10, 2010

Error Analysis

http://2.bp.blogspot.com/_y62bUPRm_F8/TIWKIbktdsI/AAAAAAAAABE/TemCsmLq4cw/s1600/Page_4_Problem_9.jpg

Value of x is going up by 5 and the slope should be 10/5 or 2 not 10/1. Inserting the points, the final equation will be solved.  Y is not equal to 9+10x in the chart

http://1.bp.blogspot.com/_y62bUPRm_F8/TIWOx17uW_I/AAAAAAAAABM/Ukvh50eIPIA/s1600/Page_8_Problem_16.jpg

To have a point it must try to solve both equations. So (1,2) only solves the first one and not the second one

http://3.bp.blogspot.com/_y62bUPRm_F8/TIWPgyUgP7I/AAAAAAAAABU/-9Y0qel_LnM/s1600/Page_19_Problem_22_and_23.  

 20)shading is correct
  should be dotted line and not solid .
 #21 the solid line is correct, but the shading should be below the line, not above it.

http://4.bp.blogspot.com/_y62bUPRm_F8/TIWQyeLDOYI/AAAAAAAAABc/9X9WU4CNiug/s1600/Page_21_Problem_20_and_21.jpg

Monday, September 6, 2010

Graphing y=a|x-h|+k


y = a|x - h| + k
Although most books won't call the point (h,k) the vertex (as in quadratics) but it will either be a maximum or minimum value for the absolute value function.
If a > 0 , then (h,k) is the lowest point of the graph.  (opens upward)
If a < 0 , then (h,k) is the highest point of the graph.  (opens downward)

Types of Systems


Case 1
Case
Case 3
graph of intersecting lines
graph of parallel lines
graph with one apparent line




Independent system:
one solution point
Case 2
Case 3
graph of intersecting lines
graph of parallel lines
graph with one apparent line


Independent system:
one solution and
one intersection point
Inconsistent system:
no solution and
no intersection point
Case 3
graph of intersecting lines
graph of parallel lines
graph with one apparent line


Independent  and consistent system:
one solution and
one intersection point
Inconsistent system:
no solution and
no intersection point
Dependent system:
the solution is the
whole line
graph of intersecting lines
graph of parallel lines
graph with one apparent line